Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

811,118 users

Please help!! problem with math?

0 votes

1.What is the weight of a concrete wall that is 25 feet long, 5 feet high and 8 inches thick? Assume concrete weighs 150 pounds per cubic foot. Round to the nearest pound. 

2.How many gallons of water will a rectangular tank hold if the base is a square that is 8 feet 10 inches on one side and the tank is 10 feet 3 inches high? Round to the nearest tenth.

asked May 4, 2014 in ALGEBRA 2 by anonymous

1 Answer

0 votes

1) Volume of the rectangular prism (V) = lbh

l = 25 feet , b = 8 inches , h = 5 feet

12 inches  = 1 ft

1 inch = 1/12

8 inch = 8/12

So b = 2/3 feet

V = 25 * 2/3 * 5

V = 250/3  ft^3

If 150 pounds for cubic feet

Then (250/3) * 150 = 12500

 Concrete weighs in the prism = 12500 pounds

2) Rectangular prism base is square, so it's length and breadths are same.

l = 8 feet 10 inches , b = 8 feet 10 inches 8 inches , h = 10 feet 3 inches

10 inches  = 10/12 = 0.83 ft

3 inches = 3/12  = 0.25 ft

l = 8.83 ft, b = 8.83 ft, h = 10.25 ft

V = 8.83 * 8.83 * 10.25 = 799.18 ft ^3

1 cubic feet = 7.48 gallons

799.18 ft^3 = 799.18 * 7.48

5978.28 gallons water will hold in the tank.

answered May 5, 2014 by david Expert

Related questions

asked Jun 17, 2017 in CALCULUS by anonymous
asked Feb 11, 2015 in CALCULUS by anonymous
...