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How would you factor -2sin(4x)sin(x)-sin(4x)=0?

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I know how to find the solutions, just the factoring that I'm not used to on this one.

asked May 13, 2014 in TRIGONOMETRY by anonymous

1 Answer

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- 2sin(4x)sin(x) - sin(4x) = 0

[-sin(4x)][2sin(x) + 1] = 0

[sin(4x)][2sin(x)+1] = 0

Factoring of -2sin(4x)Sin(x)-sin(4x) = 0 is [sin(4x)][2sin(x)+1] = 0

answered May 13, 2014 by david Expert

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