Question

Find the cross-sectional area of a 4.6 cm long solenoid with 535 turns and a self-inductance of 43 µH.

Answer 1

Given

Length of the solenoid , l =  4.6 cm = 0.046 m

Number of turns, N = 535 turns

permeability μ= 4π×10^-7 T/A-m

Inductance I = 43 µH

                     = 43×10^-6 H

Calculate the cross-sectional area by using the indutance formula:

L = N² µ A / l

43×10^-6= 535² (4π×10^-7) A / 0.046

A=5.5×10^-4 cm ²