Desperately need help with b)ii

Question

Answer 1

(b).ii.

The eye point at 2n is (x_e, y_e, z_e) = 2(1, -3, 4) = (2, -6, 8).

The image point of the point (13, -1, -4) onto the view-plane in perspective projection toward the eye at 2n = (x - x_e, y - y_e, z - z_e).

= [13 - 2, -1 - (-6), (-4) - (8)]

= [11, 5, -12]

 

Comments

2n - a

{2, -6, 8} - {13, -1, -4} = {-11, -5, 12}

line x = {13, -1, -4} + t{-11, -5, 12}

x = -11t+13

y = -5t -1

z = 12t -4

normal equation: x - 3y +4z = 26

-11t +13 +15t +3 +48t -16 = 26

52t +0 = 26

t = 1/2

x  = -11/2 + 26/2 = 15/2

y = -5/2 - 1 = -7/2

z = 12/2 - 4 = 2

Might want to check this...

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Hi,good approach

Answer 2

Let me know the text book name and chapter name or source from which the questions was asked

Comments

All the questions are from the MATH160 weekly assignments at Otago University, which randomizes the numbers for the questions.

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I just scanned it and cant remember the exact chapter but it is a pearson college textbook with no answers

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Hi zoe anonymous solution is correct