Write the equation of a circle, with center of (12,-3)

Question

and containing the point (-12,7)??? Please help!!?

Answer 1

The standard form of circle equation is (x-h)² + (y-k)² = r².

Center = (h, k) = (12, -3) and the point = (-12, 7).

Radius = The distance between the two points (x₁, y₁) = (12, -3) and (x₂, y₂) = (-12, 7).

r = √[(x₂ - x₁)² + (y₂ - y₁)²] = √[(-12 - 12)² + (7 + 3)²] = √[(24)² + (10)²] = √(576 + 100) = √(676) = 26.

The circle equation is (x-12)² + (y+3)² = (26)².