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What is the limit as x approaches infinity of

0 votes

a)logx/log(2x) b)logx/log(x^2) I tried L'Hospital's Rule first but messed up along the the way? 

 

 

asked Nov 6, 2014 in PRECALCULUS by anonymous

2 Answers

0 votes

(a) Given function

image

L'Hopital's Rule :

image

image

image

image

 = 1

The solution is Lim [logx/log(2x)] = 1

 

answered Nov 6, 2014 by lilly Expert
0 votes

(b)

Given function

image

L'Hopital's Rule :

image

image

image

image

 = 1/2

The solution is Lim [logx/log(x²)] = 1/2

answered Nov 6, 2014 by lilly Expert

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