Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

811,134 users

helppp please!4

0 votes
function y=x^2 - 4x - 5, determine the following characteristic gor this function.

- number of x intercepts

-number of y intercepts

- number of turing point

- range and domain

- End behavior
asked Nov 12, 2014 in CALCULUS by anonymous

5 Answers

0 votes

(1)

y = x² - 4x - 5 .

To determine the number of x-intercepts of the graph of a quadratic function, substitute 0 for y  .
0 = x² - 4x - 5
 x² - 4x - 5 = 0
 x² - 5x + x - 5 = 0
x(x-5) +1(x-5) = 0
(x-5)(x+1) = 0
x-5 = 0 and x+1 = 0
x = 5 and x = -1
So the function has two x-intercepts .
answered Nov 12, 2014 by yamin_math Mentor
0 votes

(2)

y = x² - 4x - 5 .

To determine the number of y-intercepts of the graph of a quadratic function, substitute 0 for x  .
y = 0² - 4(0) - 5 
y = 0 - 0 -5
y =-5
So the function has one y-intercepts .
answered Nov 12, 2014 by yamin_math Mentor
0 votes

 

(3)

The function is y = x² - 4x - 5 .

Turning points are nothing but the local minimum / maximum .

To find the local minimum / maximum , equate the first derivative to zero .

y' = 2x - 4

 2x - 4 = 0

2x = 4

x = 4/2

x = 2

So the function has one turning point at x = 2 .

 

answered Nov 12, 2014 by yamin_math Mentor
0 votes

 

(4)

The function is y = x² - 4x - 5 .

We first put the equation in to the form for a translated parabola y = (h )^2 + .

Rewrite the function 

y = x² - 4x - 5

y = x² - 4x + 4 - 4 - 5

y = x² - 4x + 4 - 9

y = (x-2)² - 9

The above function represents a parabola vertex form  y = (h )^2 + .

  = 1 , h  = 2 and k  = -9 .

a  is positive number the parabola opens up and has minimum value.

When the parabola opens up it has a minimum point which is the vertex of parabola ( 2, -9)

We know that domain of the function is all possible x  values and range is all posible y  values.

 parabola domain x  =  all real numbers.

In the minimum point y  = -9  so the graph of parabola cannot be lower than -9.

Thus the range of function y  ≥ -9.

Domain of function is all real numbers.

Range of the function is  {|y  ≥ -9}.

 

answered Nov 12, 2014 by yamin_math Mentor
0 votes

(5)

The function is y = x² - 4x - 5 .

The end behavior of a polynomial function is the behavior of the graph of f(x) as approaches positive infinity or negative infinity.

The degree and the leading coefficient of a polynomial function determine the end behavior of the graph.

The given function has the even degree and leading coefficient is positive .

 So, the end behavior is: image 

answered Nov 12, 2014 by yamin_math Mentor

Related questions

asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 13, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 6, 2014 in PRECALCULUS by anonymous
asked Oct 29, 2014 in PRECALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked May 24, 2019 in CALCULUS by anonymous
asked Oct 22, 2014 in CALCULUS by anonymous
...