Derivative of y= tan(3x^2) - sec(3x^2)?

Question

please show all steps and explian ,,, ty in advance!!!@#!@#!@3

Answer 1

y = tan(3x²) - sec(3x²)

Apply derivative to each side

dy / dx = d / dx[tan(3x²) - sec(3x²)]

Apply derivative difference rule

dy / dx = d / dx[tan(3x²)] - d / dx[sec(3x²)]

dy /dx = sec²(3x²) 6x - sec(3x²)tan(3x²)6x

Take out common term 6xsec(3x²)

dy / dx = 6xsec(3x²)[sec(3x²) - tan(3x²)].