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Refraction physics

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  Light passes from diamond into air. The angle of refraction as the light emerges from the diamond is 42 degrees. The angle of incidence was___ degrees.

 

Light travelling from air into transparent material is incident at an angle of 32 degrees and refracted at an angle of 24 degrees. The index of refraction of the transparent material is ____.

 

Light of wavelength 838nm travelling through the air enters crown glass at an angle of 27.0 degrees.The wavelength of the light in the crown glass was ___nm.

 

The critical angle for a ethanol-water interface is ____ degrees

asked Nov 22, 2014 in PHYSICS by anonymous

4 Answers

0 votes

(a)

The Angle of the Refraction is 42°

We know that from Snell's law

n1sin(θi) = n2sin(θr)

sin(θi) = (n2 / n1) sin(θr)

The Refractive Index of air is 1.0003

The Refractive Index of Diamond is 2.42

sin(θi) = (1.0003 / 2.42) sin(42)

sin(θi) = 0.2765

i) = 16.05°

Therefore angle of Incidence is 16.05°.

answered Nov 22, 2014 by Lucy Mentor
0 votes

(b)

The Angle of the Incidence is 32°

The Angle of the Refraction is 24°

We know that from Snell's law

n1sin(θi) = n2sin(θr)

The Refractive Index of air is 1.0003

The Refractive Index of Diamond is 2.42

1.0003 sin(32) = n2sin(24)

n2sin(24) = 0.53

n2 = 1.303

Therefore Refractive Index of Transparent material is 1.30.

answered Nov 22, 2014 by Lucy Mentor
0 votes

(c)

The Angle of the Incidence is 27°

We know that from Snell's law

n1sin(θi) = n2sin(θr)

The Refractive Index of air is 1.0003

The Refractive Index of Crown Glass is 1.52

1.0003 sin(27) = 1.52sin(θr)

sin(θr) = 0.2987

θr = 17.38°

Snell's law in terms of Wavelength is

λ2sin(θi) = λ1sin(θr)

Wavelength of light in the air is 838 nm

λ2sin(27) = 838 * sin(17.38)

λ2  = 551.48

Therefore Wavelength of light in Crown glass is 551.48 nm.

answered Nov 22, 2014 by Lucy Mentor
0 votes

(d)

The Angle of the Refraction is 90° for Critical Angle condition

We know that from Snell's law

n1sin(θc) = n2sin(90)

n1sin(θc) = n2

The Refractive Index of Ethanol is 1.37

The Refractive Index of water is 1.33

sin(θc) = (1.33 / 1.37)

sin(θc) = 0.970

(θc) = 76.12°

Therefore Critical angle is 76.12°.

answered Nov 22, 2014 by Lucy Mentor

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