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Consider the area between the graphs x+6y=9 and x+7=y^2...?

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Consider the area between the graphs x+6y=9 and x+7=y^2...?

This area can be computed as a sum of two integrals: int. f(x)dx between a and b, and int. g(x)dx between b and c. What are the values of f(x), g(x), a, b and c?

asked Feb 10, 2015 in CALCULUS by anonymous

2 Answers

0 votes

Step 1:

The line equation is and the curve equation is .

First find the points of intersection.

and

and .

Substitute the image values and solve for corresponding values of image.

Points of intersections are image and image.

The parabola equation is .

Vertex of the parabola at image.

Step 2:

Graph the region:

.

 

answered Feb 11, 2015 by david Expert
0 votes

Contd...

Step 3:

The parabola equation is

image

The limits image,

Each vertical cross section is between top part of parabola and bottom part of parabola :

Height of cross-section image

image

The limits image,

Each vertical cross section is between the line  of parabola and bottom part of parabola :

image

image

image

Height of cross-section image.

In this case the  area is sum of two integrals is image.

Substitute the values , ,

And , .

image.

Solution:

.

 

answered Feb 11, 2015 by david Expert

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