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help?applications of integral? [work]

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asked May 16, 2015 in CALCULUS by anonymous

1 Answer

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1)

The force acting on the object is , where is in meters.

Determine the work required to move the object meters from the right of meters.

The object is moved meters from the right of meters then meters.

Determine the work required to move the object from the right of meters to  meters.

Work done in moving the object from to is defined as

.

Here and .

Work required to move the object meters from the right of meters is .

Solution:

Work required to move the object meters from the right of meters is .

answered May 16, 2015 by cameron Mentor
edited May 16, 2015 by cameron

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