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Circuit R,C, switch

0 votes

asked Jul 24, 2015 in ELECTRICAL ENGINEERING by anonymous

1 Answer

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Step 1:

At image, the switch is closed and capacitor acts as a open circuit.

The resistance image is short circuited.

The resistor image and image are in series.

The current flowing in the circuit is image.

Substitute image, image and image.

image

Therefore current flowing in the circuit is image.

Step 2:

At image, the switch is open and capacitor starts discharging.

Apply KVL for the first loop.

image

Apply KVL for the second loop.

image

Apply Laplace transform to the equation (1).

Laplace transform of constant image.

Laplace transform of integral function image.

image

answered Jul 24, 2015 by Lucy Mentor

Contd...

Apply Laplace transform to the equation (2).

image

Substitute image in equation (3).

image

Apply inverse laplace transform.

Inverse Laplace transform :image.

image.

Since the current direction is in opposite direction, image.

Current across the capacitor is image.

Solution :

Current across the capacitor is image.

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