Algebra 1 help?(two questions)?

Question

Simplify.
1.) (1-√3)(3+√2)

2.) √112x^4y^6

Answer 1

1). (1-√3)(3+√2)

= {1(3) + 1(√2) - 3(√3) -(√3)(√2)}

= { 3 + √2 -3√3 -√6}

Substitute √2 = 1.41, √3 =1.73 and√6 = 2.44 in the above equation.

= {3 +1.41 - 3(1.73) - 2.44}

= {4.41 - 5.19 - 2.44}

= {4.41 - 7.63}

= - 3.22

The solution is - 3.22

Answer 2

2.) √112x^4y^6

 = √{16(7)(x^4)(y^6)}

= √{(4^2)(7)(x^4)(y^6})

= 4√7x^2y^3

Substitute√7 = 2.6 in the above equation.

= 4(2.6)x^2y^3

= 10.4x^2y^3

The solution is 10.4x^2y^3