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What is the electric potential energy of the proton in the figure?

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The electrons are fixed and cannot move. Assume that r = 0.48 nm and d = 1.8 nm . 

I know the equation needed is Vp = q*(kq/r)
and the answer i get is -2.47 x 10^-19 but that is wrong and I can't find my error.

asked Oct 6, 2017 in PHYSICS by anonymous
reshown Oct 14, 2017 by bradely

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