(x+2)^2+(y-2)^2=4 / Write in general form

Question

I have figured how to get it into radius form but now I am lost about general form.. my original points were

(-2,4) (0,2) (-2,0) (-4,2)

(x-h)^2+ (y-k)^2=r^2

which I got my original answer of (x+2)^2+(y-2)^2=4, but I cannot seem to understand how to get it into general form.

Answer 1

Given Equation of The Circle 

(x + 2)^2 + (y - 2)^2  =  4

Expand them

(x^2 + 4x + 4) + (y^2 - 4y + 4)  =  4

x^2 + 4x + 4 + y^2 - 4y + 4 - 4  =  0

x^2 + y^2 + 4x - 4y + 4  =  0

Answer :

Genral form is x^2 + y^2 + 4x - 4y + 4  =  0.