limits!!!!!!!!!!!!!!!!!!!!!

Question

Find the limit, if one exists:

a. limx->-3[(x^2 - 9)/(2^2 + 2x - 3)]

b. limx->4[(sqrtx) + (6)]

c. limx->-inf[(x^2 + x + 1)/(2x^3 + 3x^2 + x - 2)]

Answer 1

1)

It is in the form of

Take (x+3) common

Cancel (x+3) from numerator and denominator

Substitute the value of x = -3

Cancel common terms

2)

Substitute the value of x = 4

= 8

3)

= 0