please help!! !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Question

Find the perimeter of the polygon with vertices at (1, 3), (7, 3), (7, 7), and (4, 7).

22 units

18 units

13 units

20 units

Answer 1

Given that vertices of a polygon are (1 , 3) , (7 , 3) , (7 , 7) and (4 , 7)

First take two vertices (1 , 3) (7 , 3)

In these two vertices (1 , 3) ---> (7 , 3)

Difference of x terms is 6

we have remained at height y = 3, and went from x = 1 to x = 7, so horizontally you went 6 to the right.

In the remaining two vertices (7 , 7) ---> (4 , 7)

The difference of y terms is 3

The height remained the same, you went from 7 to 4 in the x direction, that's 3 to the left.

Now take diagnol points (1 , 3) and (4 , 7)

Finally, to get back to point (1,3) - (4,7) ----> (1,3), 3 to the left and 4 down, the diagonal being 5

Therefore finally the perimater of the given polygon is 6 + 4 + 3 +5 = 18 units