How do you find the slope of the graph at the given point:

Question

 y=4x^2-5x-1 at x= (2,5) ??

Answer 1

Given that y = 4x^2 - 5x -1

Slope (m) = dy/dx = 8x - 5

Given that at point x = (2 , 5)

dy/dx = 8x - 5

Substitute x = 2

dy/dx = 8(2) - 5

         = 16 - 5 = 11

Substitute x = 5

dy/dx = 8(5) - 5

         = 40 - 5 = 35

Therefore slope is dy/dx = 11 , 35

 

Comments

Slope of the line = dy/dx = 8(2) - 5 = 16 - 5 = 11.