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9^x-4(3^x)+3=0

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this is known as indices involving equations and is done in additional math

indices-involving-equations

asked Oct 13, 2013 in ALGEBRA 2 by andrew Scholar

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1 Answer

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9^x-4(3^x)+3=0

(3^x)^2-4(3^x)+3=0

Substitute t for 3^x.

t^2-4t+3=0

(t-1)(t-3)=0

t=1,3

Substitute 3^x for t is equation t=1.

3^x=1

xln3=ln1

x=ln1/ln3=0

3^x=3

x=1

answered Oct 19, 2013 by bradely Mentor

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