find the inclination angle

Question

Find the inclination (in radians and degrees) of the line

2x+2y-5=0

Answer 1

  

Write the line equation in slope-intercept form y = mx + b, m is slope and b is y-intercept.

2x+2y-5=0

Subtract 2x to each side.

2x+2y-5-2x=0-2x

2y-5 = -2x

Add 5 to each side.

2y-5+5 = -2x+5

2y = -2x+5

Divide each side by 2.

y = -(2/2)x +5/2

y = -x +5/2

Slope(m) = -1

m = -1

Re call m = tanθ, where θ is inclination anglem = tanθ = -1

θ = -45° or  135° and 135 × ∏/180

Substitute the value of ∏ = 3.14

θ = -45° or  135° and -45 × 3.14/180 or 135 × 3.14/180

θ = -45° or  135° and -0.785 or 2.355(radians)                      (Simplify)

Since the slope is positive Tangent sign should be positive, so the line passes through the I and II quadrant.

So, inclination angle is 135°.