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evaluate for h(1/3). show all your work

h(x) = 2 x^2 - x

word-problems
evaluating-functions

asked Nov 19, 2013 in ALGEBRA 1 by rockstar Apprentice

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1 Answer

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Given function h(x) = 2x^2-x

h(1/3) = 2(1/3)^2-1/3

= 2*1/9-1/3

= 2/9-1/3

= (2-3)/9

= -1/9

h(1/3) = -1/9.

answered Dec 17, 2013 by ashokavf Scholar

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