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log7 x=log7 (4) + log7 (6) - log7 (3) find x

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Logarithms

asked Nov 21, 2013 in ALGEBRA 2 by linda Scholar

1 Answer

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log7 x = log7 (4)+log7 (6)-log7(3)

loga+logb = logab  and loga-logb = log a/b

log7 x = log7 (4*6)-log7 (3)

log7 x = log7 24-log7 (3)

log7 x = log7 (24/3)

log7 x = log7 (8)

There fore x = 8

answered Nov 21, 2013 by william Mentor

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