Given points A (2,4), B(-1,3), C(0,-2). FInd the perimeter of triangle ABC?

Question

Find the perimeter of the triangle ABC with the distance formula.

Answer 1

Given points A(2,4) B(-1,3) C(0,-2)

ABC is a triangle.

Now find the each side of triangle.

Distance between the points = sqrt[(x2-x1)^2+(y2-y1)^2]

AB = sqrt[(-1-2)^2+(3-4)^2]

=sqrt(9+1)

= sqrt(10)

= 3.16

BC = sqrt[(0+1)^2+(-2-3)^2]

= sqrt(1+25)

= sqrt(26)

= 5.09

CA = sqrt[(2-0)^2+(4+2)^2]

= sqrt(4+36)

= sqrt(40)

= 6.32

Perimeter of triangle = AB+BC+CA

= 3.16+5.09+6.32 = 14.57

Perimeter of triangle is 14.6.