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cosx(secx-cosx)=sin^2x

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prove the following identities:

asked Nov 30, 2013 in TRIGONOMETRY by payton Apprentice

1 Answer

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Recall the trigonometric identities

1/secx = cosx, cos^2x+sin^2x = 1

Left hand side = cosx(secx-cosx)

= cosxsecx-cos^2x

= cosx*1/cosx-cos^2x

= 1-cos^2x

= sin^2x

= right hand side

answered Nov 30, 2013 by william Mentor

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