Question

The longest side of an isosceles triangle is 10 cm less than twice as long as the other sides. The perimeter of the triangle is 54 cm. Find the lengths of the three sides and list them in ascending order.

Answer 1

An isosceles triangle two sides are equal.

Perimeter of triangle = a+b+c

let equal side of isosceles triangle  = x

remaing side = 2x-10

Therefore x+x+2x-10 = 54

4x-10 = 54

4x-10+10 = 54+10

4x = 64

4x/4 = 64/4

x = 16

then 2x-10 = 2*16-10 = 22

The sides of given isosceles triangle = 16,16,22