Solve for x,y,z (6y+4z=-18), (3x+3y=9),(2x-3z+12), using matrices

Question

solve for x y z by hand using matrices

Answer 1

Solve the equations by using Cramer's rule

The equations are 6y + 4z = - 18

3x + 3y = 9

2x - 3z + 12 = 0

We can able to write the above equations.

0*x + 6y + 4z = - 18 -------> (1)

3x + 3y + 0*z = 9 ----------> (2)

2x + 0*y - 3z = - 12 ---------> (3)

Convert the equations into matrix form AX = B.

A  is coefficient matrix, X  is variable matrix and B  is constant marix.

Solution