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find the equation of the line through this pair of points.

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(1,1) and (6,2).

 

asked Feb 21, 2014 in ALGEBRA 2 by futai Scholar

1 Answer

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Slope - intercept form line equation is y = mx + b, where m is slope and b is y-intercept.

Let the points are (x₁, y₁) = (1, 1) and (x₂, y₂) = (6, 2).

Slope (m) = [(y₂ - y₁)/(x₂ -x₁)]

m = [(2 - 1)/(6 - 1)]

m = 1/5.

Now, the line equation is y = (1/5)x + b.

Find the y - intercept by substituting any point in the line equation say (x, y) = (1, 1).

1 = (1/5)(1) + b

b = 1 - (1/5)

b = 4/5.

The line equation required is y = (1/5)x + (4/5).

answered Aug 28, 2014 by lilly Expert

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