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The product of two consecutive even intergers is 80. Find the two intergers

0 votes

The product of a two consecutive even integers is 80 find the two integers.

asked Feb 26, 2014 in ALGEBRA 1 by rockstar Apprentice

1 Answer

0 votes

Let one integer is x.

Then it's consecutive even integer would be x+2.

Product of the integers x(x+2) = 80

x^2+2x = 80

Subtract 80 from each side.

x^2+2x-80 = 0

x^2+10x-8x-80 = 0

x(x+10)-8(x+10) = 0

(x+10)(x-8) = 0

x+10 = 0

Subtract 10 from each side.

x = -10

and x-8 = 0

Add 8 to each side.

x = 8

If x = -10 then integers are -10,-8.

If x = 8 then integers are 10,8.

 

answered Feb 26, 2014 by ashokavf Scholar

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