Question

Find the area of ëABC to the nearest whole number if a = 20, b = 17, and c = 32.

Answer 1

Area of triangle : A = √{ s * [(s - a)(s - b)(s - c)] } → where:

s : half of the perimeter

a, b and c are the 3 sides.


s = (20 + 17 + 32)/2

s = 34.5


(s - a) = 34.5 - 20 = 14.5

(s - b) = 34.5 - 17 = 17.5

(s - c) = 34.5 - 32 = 2.5


Area(A) = √{ s * [(s - a)(s - b)(s - c)] }

A = √[34.5* (14.5 * 17.5 * 2.5)]

A = √(34.5 * 634.375)

A = √21885.9375 → A ≈ 147,938 → A ≈ 148.

Therefore, area of triangle ABC is 148 square units.