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The equations are 2x + 7= 3 and  x = 1 y . \ \

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2x + 7= 3        Equation (1)

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x = 1 y             Equation (2)

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Since x = 1 y, substitute 1 y for x in the first equation.

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2(1 y) + 7= 3

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2 2y + 7= 3          (Distributive property: \"\")

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2 + 5= 3                  (Add: \"\")  

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\"\"

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Apply subtractionn property of equality: if a = b then a c = b c.

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2 + 52 = 3 – 2      (Subtract 2 from each side)

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5y = 1                         (Simplify)

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\"\"

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Apply division property of equality: if a = b then \"\"

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\"\"                    (Divide each side by 5).

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\"\"                         (Cancel common terms).

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\"\"

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Now, find the x value by substituting  \"\"in Equation 2.

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\"\"                   (Cancel common terms).

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Write the right hand side equation with common denominator.

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\"\"                (Least common denominator of 1 and 5 is 5).

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Since denominators are same, subtract the numerators over the denominator.

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\"\"

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\"\"                        (Leat common denominator of 1 and 5 is 5).

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\"\"

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The solution is (x , y) = \"\" .