The equations are 2x + 7y = 3 and x = 1 – y . \ \
\2x + 7y = 3 Equation (1)
\x = 1 – y Equation (2)
\Since x = 1 – y, substitute 1 – y for x in the first equation.
\2(1 – y) + 7y = 3
\2 – 2y + 7y = 3 (Distributive property: )
2 + 5y = 3 (Add: )
Apply subtractionn property of equality: if a = b then a – c = b – c.
\2 + 5y – 2 = 3 – 2 (Subtract 2 from each side)
\5y = 1 (Simplify)
\Apply division property of equality: if a = b then
(Divide each side by 5).
(Cancel common terms).
Now, find the x value by substituting in Equation 2.
(Cancel common terms).
Write the right hand side equation with common denominator.
\ (Least common denominator of 1 and 5 is 5).
Since denominators are same, subtract the numerators over the denominator.
\ (Leat common denominator of 1 and 5 is 5).
The solution is (x , y) = .