First find the y-intercept value by substituing the slope and coordinates of the
\given point in the equation.
\y = mx + b (Slope-intercept form line equation)
\1 = 3 + b (Substitute 3 for m, 1 for x, and 1 for y)
\1 – 3 = 3 + b – 3 (Subtract 3 from each side)
\1 – 3 = 3 – 3 + b (Commutative property: a + b = b + a)
\1 – 3 = b (Additive inverse property: 3 – 3 = 0)
\b = – 2 (Subtract: 1 – 3 = –2)
\
Now substitute m = 3 and b = – 2 slope-intercept form line equation.
\y = 3x + (– 2)
\y = 3x – 2 (Simplify)
\
The equation of the line that passes through the point (1, 1) and has a slope of 3 is
\y = 3x – 2.