\

The impedance in one part of a series circuit is 3 + 4 j ohms.

The impedance in another part of the series circuit is 2 – 6j ohms.

The total impedance in the circuit is (3 + 4 j) + (2 – 6j) ohms.

To find the total impedance; add the real parts and the imaginary parts separately.

Real parts:

3 + 2 = 5                                

Imaginary parts: \ \

The total impedance is (5 – 2j ) ohms.