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Method 1:
\Factor the each monomial.
\36a3 b= 2 · 2 · 3 · 3 · a · a · a · b
\56ab2 = 2 · 2 · 2 · 7 · a · b · b
\The GCF is the product of the common prime factors in each monomial.
\GCF = 2 · 2 · a · b = 4ab \ \ The greatest common factor of 36a3b and 56ab2 is 4ab.
\![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")
The greatest common factor of 36a3b and 56ab2 is 4ab.
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