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Method 1:
\Factor the each monomial.
\30a3b2 = 2 · 3 · 5 · a · a · a · b · b
\24a2b = 2 · 2 · 2 · 3 · a · a · b
\The GCF is the product of the common prime factors in each monomial.
\GCF = 2 · 3 · a · a · b = 6a2b
\ The greatest common factor of 30a3b2 and 24a2b is 6a2b.![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")
The greatest common factor of 30a3b2 and 24a2b is 6a2b.