First group the coefficients and variables.
\(10x3y)(– 2xy2) = (10 · – 2) (x3 · x) (y · y2)
\= (– 20) (x3 · x) (y · y2) (Multiply: 10 · – 2 = – 20)
\Since base is common, apply the product of powers property: am · an = am + n.
\= (– 20) (x3 + 1) (y1 + 2 )
\= – 20x4y3 (Add exponents: 3 + 1 = 4 and 1 + 2 = 3)
\Product of (10x3y)(– 2xy2) is – 20x4y3.
\