$\"\"$

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The equations are

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$\"\"$ Equation (1)

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$\"\"$ Equation (2)

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Since the coefficients of the a-terms are same, you can eliminate these terms

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by adding the equations. Subtract the equations to eliminate variable a.

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Write the equations in column form and subtract the corresponding columns. \ \

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$\"\"$

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$\"\"$

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$\"\"$ (Divide each side by negative 6)

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$\"\"$ (Cancel common terms) \ \

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$\"\"$ (Divide: $\"\"$ ) $\"\"$

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Now substitute 3 for b in either equation to find the value of a.

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$\"\"$ (Equation 1)

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$\"\"$ (Replace b by 3)

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$\"\"$ (Multiply: $\"\"$ )

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$\"\"$ (Subtract 15 from each side)

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$\"\"$ (Additive inverse property: $\"\"$ )

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$\"\"$ (Subtract: $\"\"$ )

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$\"\"$ (Divide each side by 13)

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$\"\"$ (Cancel common terms)

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$\"\"$ (Divide: $\"\"$ )

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The solution is $\"\"$ .

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$\"\"$

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The solution is $\"\"$ .

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