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The equation are inslope-intercept form y = mx + b.

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Make a table to find the solution that satisfies both equations.

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\ x \	\ y₁ = 3x – 8 \	\ y₁ \	\ y₂ = x – 8 \	\ y₂ \	\ (x₁, y₁) \	\ (x₂, y₂) \
\ –1 \	\ y₁ = 3(–1) – 8 \	\ – 11 \	\ y₂ = – 1– 8 \	\ – 9 \	\ (–1, –11) \	\ (–1, – 9) \
\ 0 \	\ y₁ = 3(0) – 8 \	\ – 8 \	y₂ = 0 – 8	\ – 8 \	\ (0, – 8) \	\ (0, – 8) \
\ 1 \	\ y₁ = 3(1) – 8 \	\ – 5 \	y₂ = 1– 8	\ – 7 \	\ (1, – 5) \	\ (1, – 7) \
\ 2 \	\ y₁ = 3(2) – 8 \	\ – 2 \	y₂ = 2 – 8	\ – 6 \	\ (2, – 2) \	\ (2, – 6) \

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Since the ordered pair (0,– 8) satisfying the both equations,the solution of the sysytem is (0,– 8). $\"\"$

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The solution of the system is (0,– 8).