The equations are
\ (Equation (1)
(Equation (2)
Solve the equation 2 for variable c in terms of the variable d.
\Apply subtraction property of equality; if a = b, then .
(Subtract 3d from each side)
(Apply additive inverse property:
)
Substitute for c in equation 1.
Distribute terms using distributive property: a(b – c) = ab – ac.
\ (Multiply:
)
(Add:
)
Apply subtraction property of equality; if a = b, then .
(Subtract 40 from each side)
(Subtract: 10 – 40 = - 30)
(Apply additive inverse property: 40
40 = 0)
Apply division property of equality: if a = b, then.
(Divide each side by negative 10)
(Cancel common terms) \ \
(Divide:
)
Substitute for d in
.
(Multiply:
)
(Subtract:
)
The solution is (1, 3).