\"\"

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Given function \"\".

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The coefficient of \"x is 1,

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The possible rational zeros must be a factor of the constant term 56.

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The possible rational zeros are \"plus-minus.

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
\

     p

\ 		\

     1

\ 		\

  \"\"5

\ 		\

  \"\"22

\ 		\

  56

\
\

    1

\ 		\

     1

\ 		\

  \"\"4

\ 		\

  \"\"26

\ 		  30
\

    1

\ 		\

     1

\ 		\

  \"\"3

\ 		\

  \"\"28

\ 		   0
\

    1

\ 		     1 \

  \"\"2

\ 		  \"\"28 \

\"\"28

\
\

    1

\ 		\

     1

\ 		\

  \"\"1

\ 		\

  \"\"23

\ 		\

\"\"36

\
\

\"\"

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One zero is 2.there are one zero at x = 2 ,the equation is

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\"straight

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\"x                                  (Substitute f(x) = 0)

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\"x                         (Rewrite \"\"as sum of \"\")

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\"x                       (Apply Factors the left side)

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\"open

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x = 7, \"\"4 and 2

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\"\"

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The rational zeros are 7, \"\"4 and 2.