\"\"

\

First find the slope of the line \"\".

\

Rewrite the line in slope-intercept form y = mx + b, where m is slope and b is y-intercept.

\

Apply addition property of equality: If a = b than a + c = b + c.

\

\"\"            (Add 2y to each side)

\

\"\"                            (Apply additive inverse property: \"\")\"\"

\

Apply subtraction property of equality: If a = b than a \"\" c = b \"\" c.

\

\"\"                (Subtract 6 from each side)

\

\"\"                            (Apply additive inverse property: \"\")

\

\"\"                     (Divide each side by 2)

\

\"\"                            (Cancel common terms)

\

Compare the equation with slope-intercept form and find the slope of the line.

\

= \"\"

\

\"\"

\

If two lines are perpendicular, the slope (m1) of one line is opposite reciprocal of the second line slope (m2). It can be represented as, \"\".

\

Slope of the line perpendicular to given line is \"\"

\

So, slope of the new line = \"\".\"\"

\

Graph the line using given point and slope.

\

1.      Draw a coordinate plane.

\

2.      Plot the given point (4, \"\"2).

\

3.   Find the next point using \"\". Start at (4, \"\"2) and go down 2 units and 3 unit right, then mark a dot and label it.

\

4.   Draw a line through these points.

\

\

    \"Graph\"\"

\

Graph of the line passing through the point (4, \"\"2) and slope \"\" is

\

\"Graph