\"\"

\

The equation is \"\".

\

Find the y-intercept.

\

The y-intercept is the value of y, when x = 0.

\

\"\"                  (Substitute x = 0 in original equation)

\

\"\"                               (Apply Zero propduct property: \"\")

\

Apply division property of equality: if a = b, then\"\".

\

\"\"                          (Divide each side by 5)

\

\"\"                                    (Cancel common terms)

\

The y-intercept is 2, so the graph intersects the y-axis at (0, 2).\"\"

\

First find the slope of the line \"\".

\

Rewrite the line in slope-intercept form y = mx + b, where m is slope and b is y-intercept.  

\

Apply subtraction property of equality: if a = b, then\"\".

\

\"\"         (Subtract 2x from each side)

\

\"\"                           (Apply additive inverse property: \"\")

\

\"\"                   (Divide each side by 5)

\

\"\"                         (Cancel common terms)

\

Compare the equation with slope-intercept form and find the slope of the line.

\

= \"\"

\

\"\"

\

If two lines are perpendicular, the slope (m1) of one line is opposite reciprocal of the second line slope (m2). It can be represented as, \"\".

\

Slope of the line perpendicular to given line is \"\"

\

So, slope of the new line = \"\".\"\"

\

Graph the line using given point and slope.

\

1.      Draw a coordinate plane.

\

2.      Plot the given point (0, 2).

\

3.   Find the next point using \"\". Start at (0, 2) and go up 5 units and 2 units right, then mark a dot and label it.

\

4.   Draw a line through these points.

\

\

    \"Graph\"\"

\

Graph of the line passing through the point (0, 2) and slope \"\" is

\

\"Graph