Since the matrices are equal, the corresponding elements are equal.
\Write two linear equations.
\3x + 2=23
\– 4y – 1=15
\First consider the equation 1.
\3x + 2=23 (subtract 2 from each side)
\3x=21 (subtract: 23 – 2=21)
\ (Divided each side by 3)
x =7 (Divide: )
Next consider the second equation.
\-4y - 1=15 (Add 1 to each side)
\-4y = 16 (Add: 15 + 1 = 16)
\ (Divided each side by 4)
– y = 4 (Divide:)
y = – 4 (Multiply each side by negative one)
The solution is (7, – 4)
\