The equation is j + 17 – 23 = –7.
\j – 6 = –7 (Subtract: 17 – 23 = –6)
\Apply addition property of equality: If a = b then a + c = b + c.
\j – 6 + 6 = –7 + 6 (Add 6 to each side)
\j = –7 + 6 (Apply additive inverse property: –6 + 6 = 0)
\j = –1 (Add: –7 + 6 = –1)
Check:
\To check the solution, substitute j = –1 in original equation.
\j – 6 = –7 –1 – 6 = –7
–7 = –7 (Add: –1 – 6 = –7)
\The statement is true.
The value of j = –1.