\"\" \"\"

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The given line is \"\".

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Above line is slope - intercept form \"\".

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So, given line has a slope of(\"\") = 3.

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So, a line parallel to it has a slope of  \"\".

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Because you know the slope and a point on the line,

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Use point - slope form \"\" to write an equation of the line.

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Let \"\"\"\" and slope(\"\") = 3.

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\"\"                      (Substitute 8 for \"\"2 for \"\" and \"\"3)\"\"

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Rewrite in slope - intercept form \"\".

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\"\"                   (Apply distributive property: \"\")

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\"\"                         (Multiply: \"\") \"\"

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Apply addition property of equality: If a = b then a + c = b + c.

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\"\"              (Add 8 to each side)

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\"\"                   (Apply additive inverse property: \"\")

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\"\"                         (Apply additive identity property: \"\")

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\"\"                               (Add: \"\")\"\"

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Check:

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To check the solution substitute \"\" = \"\" in \"\".

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\"\"

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\"\"                                 (Multiply: \"\")

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\"\"                                       (Add: \"\")

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The equation satisfies the condition.

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So,The equation of the line is  \"\".\"\"

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The equation of the line is  \"\".