\"\"\"\"

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The given line is \"\".

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Above line is slope - intercept form \"\".

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So, given line has a slope of(\"\") = \"\".

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So, a line perpendicular to it has a slope of  \"\".

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Because you know the slope and a point on the line,

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Use point - slope form \"\" to write an equation of the line.

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Let \"\"\"\" and slope(\"\") = \"\"3.

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\"\"           (Substitute 1 for \"\" , 4 for \"\" and \"\" = \"\"3)\"\"

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Rewrite in slope - intercept form \"\".

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\"\"  (Apply distributive property: \"\")

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\"\"            (Multiply: \"\") \"\"

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Apply addition property of equality: If a = b then a + c = b + c.

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\"\"(Add 1 to each side)

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\"\"      (Apply additive inverse property: \"\")

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\"\"            (Apply additive identity property: \"\")

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\"\"                 (Add: \"\")\"\"

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Check:

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To check the solution substitute \"\" = \"\" in \"\".

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\"\"

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\"\"                 (Multiply: \"\")

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\"\"                               (Subtract: \"\")

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The equation satisfies the condition.

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So,The equation of the line is  \"\".\"\"

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The equation of the line is  \"\".