\"\"\"\"

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The given line is \"\".

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Above line is slope - intercept form \"\".

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So, given line has a slope of(\"\") = 0.

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So, a line perpendicular to it has a slope of  \"\".

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Because you know the slope and a point on the line,

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Use point - slope form \"\" to write an equation of the line.

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Let \"\"\"\" and slope(\"\") = \"\".

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\"\"(Substitute 2 for \"\" , \"\"6 for \"\" and \"\" =\"\")\"\"

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Rewrite in slope - intercept form \"\".

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\"\"      (Product of two same signs is positive)

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Apply multiplication property of equality:If a = b then a \"\" c = b \"\" c.

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\"\"(Multiply each side by 0)

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\"\"       (Cancel common terms)

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\"\"                  (Apply zero product property: \"\")

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\"\"               (Apply distributive property: \"\")

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\"\"                       (Apply multiplicative identity property: \"\")\"\"

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Apply subtraction property of equality:If a = b then a \"\" c = b \"\" c.

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\"\"            (Subtract 6 from to each side)

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\"\"                  (Apply additive inverse property: \"\")

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\"\"                          (Apply additive identity property: \"\", \"\") \"\"

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Check:

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To check the solution substitute \"\" = \"\" in \"\".

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\"\"

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The equation satisfies the condition.

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So,The equation of the line is  \"\".\"\"

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The equation of the line is  \"\".