\"\"

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Given point is \"open.

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The direct variation equation is \"Syntax.

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Solve for a:

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Substitute \"open in \"Syntax

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\"Syntax

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\"Syntax                       (Multiply: \"5)

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\"Syntax                  (Divide each side by 5)

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\"Syntax                       (Cancel common terms)

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\"Syntax                            (Divide: \"fraction)\"\"

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Substitute \"Syntax in \"Syntax

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\"y

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\"y                         (Multiply: \"minus)\"\"

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Given that \"y  substitute in \"y.

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\"minus

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\"Syntax                  (Divide each side by negative 3)

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\"x                              (Cancel common terms) \ \ \"\"

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The value of \"x.