Method 1:
\Factor the each monomial.
\32mn2 = 2 · 2 · 2 · 2 · 2 · m · n · n
\16n = 2 · 2 · 2 · 2 · n
\12n3 = 2 · 2 · 3 · n · n · n
\The GCF is the product of the common prime factors in each monomial.
\GCF = 2 · 2 · n = 4n
\ The greatest common factor of 32mn2,16n and 12n3 is 4n.
The greatest common factor of 32mn2,16n and 12n3 is 4n.