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Method 1:

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Factor the each monomial.

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32mn2 = 2 · 2 · 2 · 2 · 2 · m · n · n

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16n = 2 · 2 · 2 · 2 · n

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12n3 2 · · 3 · n · n  · n 

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The GCF is the product of the common prime factors in each monomial.

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GCF = 2 · 2 · = 4n

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The greatest common factor of 32mn2,16n and 12n3 is 4n.\"\"

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The greatest common factor of 32mn2,16n and 12n3 is 4n.