![\"\"](\"/userfiles/image/steps_images/step1.JPG\")
From the diagram there are 45°- 45°- 90° triangles are formed.
\The 45°- 45°- 90° triangles has the property that the length of its hypotenuse is
\![\"\"](\"plugins/fckeditor_wiris/integration/showimage.php?formula=399c0c3256982546aac098aa31c63b0a.png\")
times to the length of a leg.
Therefore, the length between the home plate and 2nd base is times to the
length between the bases.
\The length between bases is 90 feet.
\Thus, length between the home plate and 2nd base is ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=63fd3247aee6c92e60d5e2e446bd1de3.png\")
or about 127.26 ft.![\"\"](\"/userfiles/image/steps_images/solution.JPG\")
The distance between the home plate and 2nd base is ![\"\"](\"plugins/fckeditor_wiris/integration/showimage.php?formula=63fd3247aee6c92e60d5e2e446bd1de3.png\")
or about 127.26 ft.