$\"\"$

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Four times the lesser of two consecutive even integers is $\"\"$ less than twice the greater number.

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Find the integers.

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Let $\"\"$ be the first even integer and $\"\"$ be the next consecutive even integer.

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Solve the equation:

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$\"\"$ (Original equation)

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$\"\"$ (Distributive property: $\"\"$ )

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$\"\"$ (Simplify)

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$\"\"$ (Subtract $\"\"$ from each side)

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$\"\"$ (Apply additive inverse property : $\"\"$ )

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$\"\"$ (Divide each side by $\"\"$ )

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$\"\"$ (Cancel common terms)

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Since,the first integer $\"\"$ is $\"\"$ .

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Second integer $\"\"$ is $\"\"$ .

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Therefore,the consecutive even integers are $\"\"$ and $\"\"$ . $\"\"$

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The consecutive even integers are $\"\"$ and $\"\"$ .